package listbyorder.access001_100.test21;

import listbyorder.utils.ListNode;

/**
 * @author code_yc
 * @version 1.0
 * @date 2020/5/29 14:06
 */
public class Solution2 {

    // 解法二： 递归
    public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
        if (l1 == null) return l2;
        if (l2 == null) return l1;
        if (l1.val < l2.val) {
            l1.next = mergeTwoLists(l1.next, l2);
            return l1;
        } else {
            l2.next = mergeTwoLists(l1, l2.next);
            return l2;
        }
    }
}
